Lesson AC inductance · Inductance and reactance
Inductive reactance
Inductive reactance (XL) is the current-limiting effect of an inductor in AC, measured in ohms — like resistance, but caused by induced voltage, not heat. Formula: XL = 2πfL. Higher frequency or more inductance means more opposition to AC current. At 60 Hz, memorize 2πf ≈ 377 for quick field estimates.
Reactance vs resistance
Resistance (R) limits current by dissipating energy as heat. Inductive reactance limits current by induced counter-voltage — no intentional heat in an ideal inductor.
Both are measured in ohms. In calculations you can substitute XL for R in Ohm's law when the circuit is purely inductive:
I = E / XL
Symbol: XL ("X sub L"). General reactance is X; inductive is XL; capacitive (later course) is XC.
Think of XL as dynamic opposition — it exists only while current is changing, which in AC is all the time.
The formula XL = 2πfL
XL = 2πfL
Where:
| Symbol | Meaning |
|---|---|
| XL | Inductive reactance (Ω) |
| 2π | Constant ≈ 6.2832 |
| f | Frequency (Hz) |
| L | Inductance (H) |
XL depends on two things you control or read from the nameplate:
- Physical inductance L — turns, core material, core size, gap
- Line frequency f — 60 Hz in most of North America; 50 Hz in much of Europe and Asia
Double the inductance → double XL. Double the frequency → double XL.
Why frequency is in the formula
Induced voltage depends on how fast flux cuts the conductors. Higher frequency means the AC waveform completes more cycles per second — the field changes faster — more induced volts → higher XL.
Example from the book: an inductor at 60 Hz draws 24 A from 480 V (XL = 20 Ω). Same coil at 400 Hz:
- First find L: L = XL / (2πf) = 20 / 377 ≈ 0.053 H
- At 400 Hz: XL = 2π × 400 × 0.053 ≈ 133 Ω
- New current: I = 480 / 133 ≈ 3.6 A
Same coil, same voltage — frequency change dramatically changes current.
Field shortcut at 60 Hz:
2π × 60 ≈ 377
So: XL ≈ 377 × L and L ≈ XL / 377
Finding L when XL is known
Rearrange:
L = XL / (2πf)
Example: 36 V, 400 Hz, I = 0.2 A
- XL = E / I = 36 / 0.2 = 180 Ω
- L = 180 / (2π × 400) ≈ 0.0716 H
Example: 120 V, 60 Hz, coil 0.8 H, negligible wire R
- XL = 2 × 3.1416 × 60 × 0.8 ≈ 301.6 Ω
- I = 120 / 301.6 ≈ 0.398 A
Always find XL first when solving for current in a pure-L branch.
What builds inductance L
L is fixed by construction, not by the voltage you apply:
- More turns → more L
- Turns closer together → more L
- Iron or ferrite core → much more L than air
- Larger core cross-section → more L
Once the part is built, L is constant. Only f and XL change when you move it to another frequency.
Units: henry (H). Field values are often millihenries (mH).
| H | mH |
|---|---|
| 1 H | 1000 mH |
| 0.106 H | 106 mH |
Using XL in Ohm's law
For a pure inductive branch (Q high, wire R negligible):
| Find | Formula |
|---|---|
| Current | I = E / XL |
| Reactance | XL = E / I |
| Inductance | L = XL / (2πf) |
| Frequency | f = XL / (2πL) |
When wire resistance matters (real motor coil, contactor), total opposition is impedance Z, not XL alone — covered in later lessons.
Worked comparison: 60 Hz vs 50 Hz ballast
A 0.5 H choke at 120 V:
- At 60 Hz: XL = 377 × 0.5 ≈ 188.5 Ω → I ≈ 0.64 A
- At 50 Hz: XL = 314 × 0.5 ≈ 157 Ω → I ≈ 0.76 A
Running a 50 Hz rated choke on 60 Hz increases current roughly 20% — enough to overheat over time. Running 60 Hz equipment on 50 Hz usually lowers current but may affect saturation and performance — still a mismatch to avoid.
Field case
Situation. A 480 V, 60 Hz reactor nameplate is illegible. An identical unit on another line draws 18 A with 324 V measured across the reactor (rest of drop elsewhere). De-energized, ohmmeter reads 1.2 Ω wire resistance.
Steps.
- XL ≈ E / I = 324 / 18 = 18 Ω (if R negligible — check Q later)
- L = 18 / 377 ≈ 0.048 H order value
- VAR rating ≈ E × I = 324 × 18 ≈ 5832 VAR minimum
Applied lesson. XL from running amps and volts gives you orderable inductance when the paint is gone — but verify wire R before assuming pure inductance.
In the field
Symptom
Reactor runs hot; current higher than sister unit
Where to look
Line reactors, ballasts, filter inductors
Likely causes
- Wrong f, shorted turns (↓L but abnormal current pattern), line voltage high
What to measure
- f at panel, volts across coil, amps through coil, cold R
What not to do
- Use DC ohms reading as XL
Checklist
- I write XL = 2πfL from memory
- I use 377 as 2πf at 60 Hz
- I rearrange to L = XL / (2πf)
- I explain that XL rises with both L and f
- I apply I = E / XL for pure inductive branches
- I convert between H and mH