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Lesson AC inductance · Inductance and reactance

Inductive reactance

Inductive reactance (XL) is the current-limiting effect of an inductor in AC, measured in ohms — like resistance, but caused by induced voltage, not heat. Formula: XL = 2πfL. Higher frequency or more inductance means more opposition to AC current. At 60 Hz, memorize 2πf ≈ 377 for quick field estimates.

1

Reactance vs resistance

Resistance (R) limits current by dissipating energy as heat. Inductive reactance limits current by induced counter-voltage — no intentional heat in an ideal inductor.

Both are measured in ohms. In calculations you can substitute XL for R in Ohm's law when the circuit is purely inductive:

I = E / XL

Symbol: XL ("X sub L"). General reactance is X; inductive is XL; capacitive (later course) is XC.

Think of XL as dynamic opposition — it exists only while current is changing, which in AC is all the time.

2

The formula XL = 2πfL

XL = 2πfL

Where:

SymbolMeaning
XLInductive reactance (Ω)
2πConstant ≈ 6.2832
fFrequency (Hz)
LInductance (H)

XL depends on two things you control or read from the nameplate:

  1. Physical inductance L — turns, core material, core size, gap
  2. Line frequency f — 60 Hz in most of North America; 50 Hz in much of Europe and Asia

Double the inductance → double XL. Double the frequency → double XL.

3

Why frequency is in the formula

Induced voltage depends on how fast flux cuts the conductors. Higher frequency means the AC waveform completes more cycles per second — the field changes faster — more induced volts → higher XL.

Example from the book: an inductor at 60 Hz draws 24 A from 480 V (XL = 20 Ω). Same coil at 400 Hz:

  • First find L: L = XL / (2πf) = 20 / 377 ≈ 0.053 H
  • At 400 Hz: XL = 2π × 400 × 0.053 ≈ 133 Ω
  • New current: I = 480 / 133 ≈ 3.6 A

Same coil, same voltage — frequency change dramatically changes current.

Field shortcut at 60 Hz:

2π × 60 ≈ 377

So: XL ≈ 377 × L and L ≈ XL / 377

4

Finding L when XL is known

Rearrange:

L = XL / (2πf)

Example: 36 V, 400 Hz, I = 0.2 A

  1. XL = E / I = 36 / 0.2 = 180 Ω
  2. L = 180 / (2π × 400) ≈ 0.0716 H

Example: 120 V, 60 Hz, coil 0.8 H, negligible wire R

  1. XL = 2 × 3.1416 × 60 × 0.8 ≈ 301.6 Ω
  2. I = 120 / 301.6 ≈ 0.398 A

Always find XL first when solving for current in a pure-L branch.

5

What builds inductance L

L is fixed by construction, not by the voltage you apply:

  • More turns → more L
  • Turns closer together → more L
  • Iron or ferrite core → much more L than air
  • Larger core cross-section → more L

Once the part is built, L is constant. Only f and XL change when you move it to another frequency.

Units: henry (H). Field values are often millihenries (mH).

HmH
1 H1000 mH
0.106 H106 mH
6

Using XL in Ohm's law

For a pure inductive branch (Q high, wire R negligible):

FindFormula
CurrentI = E / XL
ReactanceXL = E / I
InductanceL = XL / (2πf)
Frequencyf = XL / (2πL)

When wire resistance matters (real motor coil, contactor), total opposition is impedance Z, not XL alone — covered in later lessons.

7

Worked comparison: 60 Hz vs 50 Hz ballast

A 0.5 H choke at 120 V:

  • At 60 Hz: XL = 377 × 0.5 ≈ 188.5 Ω → I ≈ 0.64 A
  • At 50 Hz: XL = 314 × 0.5 ≈ 157 Ω → I ≈ 0.76 A

Running a 50 Hz rated choke on 60 Hz increases current roughly 20% — enough to overheat over time. Running 60 Hz equipment on 50 Hz usually lowers current but may affect saturation and performance — still a mismatch to avoid.

8

Field case

Situation. A 480 V, 60 Hz reactor nameplate is illegible. An identical unit on another line draws 18 A with 324 V measured across the reactor (rest of drop elsewhere). De-energized, ohmmeter reads 1.2 Ω wire resistance.

Steps.

  1. XL ≈ E / I = 324 / 18 = 18 Ω (if R negligible — check Q later)
  2. L = 18 / 377 ≈ 0.048 H order value
  3. VAR rating ≈ E × I = 324 × 18 ≈ 5832 VAR minimum

Applied lesson. XL from running amps and volts gives you orderable inductance when the paint is gone — but verify wire R before assuming pure inductance.

In the field

Symptom

Reactor runs hot; current higher than sister unit

Where to look

Line reactors, ballasts, filter inductors

Likely causes

  1. Wrong f, shorted turns (↓L but abnormal current pattern), line voltage high

What to measure

  1. f at panel, volts across coil, amps through coil, cold R

What not to do

  • Use DC ohms reading as XL

Checklist

  • I write XL = 2πfL from memory
  • I use 377 as 2πf at 60 Hz
  • I rearrange to L = XL / (2πf)
  • I explain that XL rises with both L and f
  • I apply I = E / XL for pure inductive branches
  • I convert between H and mH

Common mistakes

Symptom Typical cause Action
Symptom Current way off after "same H" swap
Typical cause Different frequency supply
Action Recalculate XL with actual f
Symptom Adding XL like resistors in parallel wrongly
Typical cause Confusing with R formulas
Action Series XL adds; parallel uses reciprocal (next lesson on L combinations)
Symptom Using 377 at 50 Hz
Typical cause Wrong constant
Action Use 2π × 50 ≈ 314
Symptom Ignoring wire R on small coil
Typical cause Pure-L math on real part
Action Check Q; use Z if R significant